Solving Q for an Unknown Gas - Warren's Homework

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To solve for Q of an unknown gas, the equation Q = (molar heat capacity)(moles)(∆T) is applicable even when using molar heat capacity instead of specific heat. Given the values, Q is calculated as 102.5 J using 2.00 J/mol°C for molar heat capacity, 2.5 moles, and a temperature change of 20.5 °C. The constant pressure condition simplifies the calculation, allowing the use of molar heat capacity directly. The units are consistent, confirming the calculation's validity. This method effectively determines the heat transfer for the gas.
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Homework Statement


Unknown gas:
Solving for Q
2.5 moles
Molar heat capacity 2.00J/mol°C
∆T=20.5
P constant .995

My question is I'm used to seeing this eqn. with specific heat and grams. Since given molar heat capacity and moles does it still work?
Constant P allows me to ignore it in this type of eqn?

Homework Equations


The Attempt at a Solution



Q=(2.00J/mol°C)(2.50 mol)(20.5 °C) = 102.5 J

Thanks,

Warren
 
Last edited:
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Your units match up, and it looks good to me.
 

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