Solving Q1 of MathIII Paper60: Ricci Identity & Killing Vectors

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Hi I'm trying Q1 of this paper:
http://www.maths.cam.ac.uk/postgrad/mathiii/pastpapers/2005/Paper60.pdf
and have got to the bit where I need to show that \xi_{b;ca}=-R_{bca}{}^d \xi_d

Now I know that R_{bca}{}^d \xi_d=R_{bcad} \xi^d = R_{adbc} \xi^d = \nabla_b \nabla_c \xi_a - \nabla_c \nabla_b \xi_a

where I got that last equality by rearranging the Ricci identity \nabla_c \nabla_d Z^a - \nabla_d \nabla_c Z^a = R^a{}_{bcd}Z^b

So then we have -R_{bca}{}^d \xi_d = \nabla_c \nabla_b \xi_a - \nabla_b \nabla_c \xi_a = -\nabla_c \nabla_a \xi_b + \nabla_b \nabla_a \xi_c
where I used the Killing property on the first term to get a \xi_b term like we are looking for but I can't quite manipulate it into the final answer. Can anybody see what I am doing wrong?And then in the last bit, can somebody help me to show that if the Killing vector and the first derivative vanish at a point then they vanish everywhere?

And what about the final part about how many linearly independent Killing vectors can there be? My notes say that a n dimensional spacetime is maximally symmetric if there exist \frac{n(n+1)}{2} linearly independent Killing vectors. But I don't actually know whether this is relevant to the question at hand or not?

Thanks.
 
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I would start with

R_{[ij|k]l} = 0

from which you get based on Ricci's identity in the absence of torsion

\nabla_{[k}\nabla_{j}\xi_{i]} = 0

from which you should get by expansion into the 6 possible terms and regrouping based on

\nabla_{(i}\xi_{j)} = 0

an expression showing you the right way to get the final identity.
 
dextercioby said:
I would start with

R_{[ij|k]l} = 0

from which you get based on Ricci's identity in the absence of torsion

\nabla_{[k}\nabla_{j}\xi_{i]} = 0

from which you should get by expansion into the 6 possible terms and regrouping based on

\nabla_{(i}\xi_{j)} = 0

an expression showing you the right way to get the final identity.

Thanks for your reply. What do you mean by R_{[ij|k]l} = 0? Is there supposed to be another vertical line in there somewhere to indicate one of the indices is not antisymmetrised?
 
No, sorry, the vertical line comes from the Youg tableau. So disregard it. I put it there from discussions on such tensors outside GR that have not left my mind yet.
 
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