Solving Rifle Recoil & Force: A 30-06 Hunting Rifle Case Study

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The discussion focuses on calculating the recoil speed of a 30-06 hunting rifle and the average force exerted on the hunter's shoulder. The recoil speed was correctly calculated as 1.6049 m/s when the bullet is fired. However, the calculated average force of approximately 3.16 N seems too low for the impact experienced during firing. Participants suggest that the average acceleration of the rifle should be considered to accurately determine the force on the shoulder. The conversation emphasizes the need for a more thorough approach to the calculations to reflect realistic forces involved.
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Homework Statement


Already Solved(Part 1) :A 30-06 caliber hunting rifle fires a bullet of mass of 0.00689 kg with a velocity of 778 m/s to the right. The rifle has a mass of 3.34 kg. What is the recoil speed of the rifle as the bullet leaves the rifle. Answer in units of m/s. Answer is 1.6049

Part 2: If the rifle is stopped by the hunter's shoulder in a distance of 1.36 cm, what is the magnitude of the average force exerted on the shoulder by the rifle? Answer in units of N.

Homework Equations


1. Vaverage= O + Vi(1.6049) / 2
2.∆T = 2x/ Vi
3. F∆t=∆mv
4. F=MVi /∆t



The Attempt at a Solution


1. 0+1.6049/2 = 0.80245
2. 2(1.36) / 1.6049 = 1.694809645
4. (3.34)(1.6049) / 1.694809645 = 3.162813013.
This was my answer by I know that the force is too low for a bullet hitting a shoulder...What did I do wrong?
 
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Can you not work out the average acceleration of the rifle and then the magnitude of the force from that?
 
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