Solving the Largest Number in a Set of 8 Consecutive Numbers: Math Question ASAP

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The problem involves finding the largest number, n, in a set of 8 consecutive numbers with an average of X. The numbers can be expressed as n, n-1, n-2, ..., n-7. The average is calculated as the sum of these numbers divided by 8, leading to the equation (n + (n-7)) / 2 = X. Simplifying this yields 2X = 2n - 7, which can be rearranged to find n in terms of X as n = 2X + 7. Thus, the largest number in the set is determined by this formula.
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If the average of 8 consecutive numbers is X. What is the largest number in terms of X?

I have no idea on how to solve this question. thx.
 
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let the largest number be n, the rest is n-1,n-2...n-7...the average of these eight number is X... you have 1 equation and two unknow... so you can find n in term of X
 
the sum of 8 consecutive numbers can be written as such: (n+n+7)8/2 following the whole (n1+nfinal)(total/2) form. Using this, we get that (n+n+7)4/8=x or 2x=2n+7, meaning that n=(2x-7)2
 
o ok i c, but u must set another variable.
 
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