Solving the Yo-Yo's Limit Angle for Acceleration

AI Thread Summary
The discussion focuses on determining the limit angle θ for a yo-yo's acceleration, where the yo-yo transitions from rolling positively to negatively based on the applied force T at angle θ. The user outlines their approach by incorporating forces such as weight, normal reaction, and static friction into their equations. They express confusion over consistently arriving at nonsensical answers when solving the system of equations, suspecting an error in their sign conventions. The conversation highlights the importance of torque and rotational dynamics in analyzing the yo-yo's motion. Ultimately, the user expresses satisfaction after gaining clarity on the problem.
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Homework Statement


We have a yo-yo, formed by a little cylinder tied to a little rope, and two big disks as wheels, one for each side of the central cylinder. We do a force T on the rope; its slope is an angle θ over the horizontal x-axis.
We are given the mass m of the cylinder, the mass M of each wheel, the radius of the cylinder R1 and the radius of each wheel R2. We want to know the limit angle θ , for the acceleration to be positive or negative.
I try to explain it better: under a certain angle, the yo-yo have a pure roll in the positive direction, over this angle it goes "back" and rolls towards the negative direction.

The Attempt at a Solution


I put in all the forces, the weight $mg$, the reaction $N$, and the friction force (static, since it's roling) towards the left side.
My equations are:
T*sinθ + N = m*g
T*cosθ - f_{s} = m*a_{cm}
f_{s}*R2 - T*R1 = I_{G}*α = I_{G} * a_{cm} / R2

But I'm always obtaining a non-sense answer solving the system, I guess I'm doing wrong something about the signes. Can someone help me?
Thanks a lot.
 
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when it rolls, its rotation is around the point where it contacts the ground.
If the torque around this point is zero, it does not roll (alpha = 0).
 


Thank you very much| Now I got it :D
 
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