Solving Two-Car Accident with Friction: Step-by-Step Guide

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In a two-car accident scenario, both vehicles of equal mass collide at an intersection and slide together for 9 meters before stopping. The coefficient of friction is 0.9, and the work done by friction can be expressed as 2*μ*m*g*d, but there is a noted error in this expression that requires a negative sign for the work done. Each driver claims their speed was under 14 m/s, with a third driver supporting one claim by stating the speed was no more than 12 m/s. The discussion highlights the challenges faced in solving physics problems related to the collision and subsequent motion.
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please help if u can.
Consider the following two-car accident: Two cars of equal mass collide at an intersection. Driver E was traveling eastward, and driver N, northward. After the collision, the two cars remain joined together and slide, with locked wheels, before coming to rest. Police on the scene measure the length of the skid marks to be 9 meters. The coefficient of friction between the locked wheels and the road is equal to 0.9.

i kno this question has been posted in other forums, but I am tryin to work out the work doen by friction and keep gettin it wrong,
Write an expression for the work done on the cars by friction.
Express your answer symbolically in terms of the mass of a single car, the magnitude of the acceleration due to gravity , the coefficient of sliding friction , and the distance through which the two-car system slides before coming to rest.
i get 2*mu*m*g*d which it (the web program) tells me I am off by a multiplicative factor...


Each driver claims that his speed was less than 14 meters per second (50 mph). A third driver, who was traveling closely behind driver E prior to the collision, supports driver E's claim by asserting that driver E's speed could not have been greater than 12 meters per second. Take the following steps to decide whether driver N's statement is consistent with the third driver's contention.
 
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It's doing negative work on the car. Just add a negative sign in. BTW, do you go to sydney uni at all?
 
yup, so do u i take it? nd thanks for that it was driving me crazy... couldn't work out where i was wrong
 
No probs. The whole physics asignment is driving me crazy...
 
i kno wat u mean, now I am stuck on the next question... got 12.61 m/s which is wrong... then i used 13 (cause it says to nearest integer) nd its also wrong
 
Do you have msn? Maybe we can chat through there.
 

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