Solving Vector B in Polar Notation: -3.85 and -4.59?

AI Thread Summary
Vector B, given in polar notation as (6, -130 degrees), needs to be converted to rectangular notation. The correct conversion involves using the formulas x = r * cos(θ) and y = r * sin(θ), where r is the magnitude and θ is the angle. The initial attempt yielded incorrect values of -3.85 and -4.59, likely due to confusion with angle ranges. It's important to ensure that the angle is correctly interpreted within the specified range of -180 to +180 degrees. Understanding the relationship between polar and rectangular coordinates is crucial for accurate conversions.
ramman1505
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Homework Statement


Vector B is given in polar notation as (6,-130degrees). In rectangular notation vector B is what?


Homework Equations


For this problem, take all angles between -180 and +180.


The Attempt at a Solution



I got an answer or -3.85 and -4.59. However they were the wrong answers. I suspect it has something to do with the all angles between -180 and +180 part. I took (6,50degrees) and put it in the calc. and got that answer -3.85 and -4.59. What am i doing wrong?
 
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What exactly did you do?
 
I put [6,50degrees] in the calculator and solved it for rectangular notation. Which should give me the x and y values of the rectangular notation.
 
ramman1505 said:
I put [6,50degrees] in the calculator and solved it for rectangular notation. Which should give me the x and y values of the rectangular notation.

If you use calculators to solve your problems, you'll never know how to solve them, right? So, what is the relation between polar and rectangular coordinates?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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