Solving Work & Velocity Problem: Proton & Electric Field

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A proton moving at 6.5x10^6 m/s encounters an electric field of 4500 V/m, and the discussion centers on calculating how far the proton penetrates the field before stopping. The initial calculations involve determining the proton's kinetic energy and the force exerted by the electric field. Both contributors arrive at a distance of 49 meters, which contradicts the book's answer of 10.49 meters. The participants suggest that the issue likely lies in the calculations, prompting a request for verification of the steps taken. The conversation emphasizes the importance of carefully checking each calculation to resolve the discrepancy.
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Problem: A proton moving at 6.5x10^6 m/s encounters an electric field of 4500 volt/meter.
How fall will the proton penetrate the field before stopping. (Electric field and proton are moving in opposite directions)

My attempt:
First I found the kinetic energy of the proton, then I found the force that the electric field exerted on the proton with F=Eq. The force would do the sane amount of work on the proton as the kinetic energy the proton had to make it stop so I used w=fs with w=kinetic energy and solved for s. The answer was 49m but the answer in the book is 10.49m.
Can someone tell me where I went wrong?
 
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Your idea is right... must have been your calculations that went wrong... can you show your steps?
 
Mass of proton = 1.67 x 10^-27
q of proton = 1.6 x 10^19
using ke = 1/2mv^2 kinetic energy = 3.527875 x 10^14
using F=Eq, F=7.2 x 10^16
W=f x s
W/F = S
 
I'm also getting 49m. Double check to make sure you have the question right...
 
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