# Sound Intensity Level and Hearing Problem

1. Jan 21, 2012

### Dr. S

Thank you for the help!

Last edited: Jan 21, 2012
2. Jan 21, 2012

### Dr. S

Could really use some input!

3. Jan 21, 2012

### Curious3141

It's correct, but I would've just used the inverse square law to work out the sound intensity at 2m from the one at 3m instead of calculating the power of the source.

4. Jan 21, 2012

### Dr. S

Inverse square law? How I would I go about using that here?

Thank you, by the way. :)

5. Jan 21, 2012

### Curious3141

$\frac{I_{2m}}{I_{3m}} = \frac{3^2}{2^2}$.

And you're welcome.