Sound Intensity Level and Hearing Problem

[Dr. S]

Thank you for the help!

 

[Dr. S]

Could really use some input!

 

[Curious3141]

Could really use some input!

It's correct, but I would've just used the inverse square law to work out the sound intensity at 2m from the one at 3m instead of calculating the power of the source.

 

[Dr. S]

It's correct, but I would've just used the inverse square law to work out the sound intensity at 2m from the one at 3m instead of calculating the power of the source.

Inverse square law? How I would I go about using that here?

Thank you, by the way. :)

 

[Curious3141]

Inverse square law? How I would I go about using that here?

Thank you, by the way. :)

$\frac{I_{2m}}{I_{3m}} = \frac{3^2}{2^2}$.

And you're welcome.