Dr. S
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Thank you for the help!
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Sound Intensity Level and Hearing Problem
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Dr. S
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Could really use some input!
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Dr. S said:
It's correct, but I would've just used the inverse square law to work out the sound intensity at 2m from the one at 3m instead of calculating the power of the source.
Dr. S
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Curious3141 said:
Inverse square law? How I would I go about using that here?
Thank you, by the way. :)
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Dr. S said:
[itex]\frac{I_{2m}}{I_{3m}} = \frac{3^2}{2^2}[/itex].
And you're welcome.
