Spacetime diagram based question.

AI Thread Summary
A spaceship moving at a speed of ß=4/5 has a rest length of 1 second, and a light signal is sent from the rear to the front and back. The total round trip time for an observer at rest is calculated to be 10/3 seconds. The time taken for the light to travel from the rear to the front and from the front to the rear remains unresolved, with the poster seeking assistance for these parts. The difference in synchronization of the ship's front and rear clocks is estimated to be -4/3 seconds. The discussion highlights the application of spacetime diagrams and relevant equations in solving relativistic problems.
ronsonol
Messages
2
Reaction score
0

Homework Statement


A Spaceship is moving with speed ß=4/5.

Its length at rest is 1sec. A light is turned on at the rear of the ship, reflected back from a mirror at the front.
a.) How long does an observer at rest say it takes for the light to return to the rear of the ship (total round trip time)?
b.) How long did the light take to go from the rear to the front?
c.) How long did the light take to go from the front to rear?
d.) Use the results above to determine how far out of synchronization an observer at rest says the ship's front and rear clocks are.

∆T = 2s (proper time = 2seconds) light shining from rear to front back to rear.
y=5/3

Homework Equations



∆t=y (∆t' +ß∆x')
∆T - ∆t≈=-0.5v^2∆t

The Attempt at a Solution



For Part A I used the 1st equation:
∆t = (5/3)(2s + (4/5)(0)) = 10/3s
I'm not sure if I set it up correctly, but I got it right.

I am still trying to figure out part B and part C and have attached a diagram.

Part D I'm not sure exactly how I got the correct answer but I used the 2nd equation to estimate the difference:
2-(10/3) = -4/3s
 

Attachments

  • IMAG1009.jpg
    IMAG1009.jpg
    13.6 KB · Views: 493
Physics news on Phys.org
Since this thread was moved from the Advanced to Introductory section, I thought it would be appropriate to bump, hopefully someone can offer a hint for me to continue. Thanks in advance.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top