Spacetime Inverval Invariance using Lorentz Transformations

Click For Summary
SUMMARY

The discussion focuses on proving the invariance of the spacetime interval defined by the equation -(ct)² + x² + y² + z² using Lorentz transformations. The key transformations involved are Δx' = γ(Δx - uΔt), Δy' = Δy, Δz' = Δz, and Δt' = γ(Δt - uΔx/c²). The participant successfully simplified the expression to show that the coefficient of x² is γ²(1 - u²/c²), leading to the conclusion that the spacetime interval remains invariant under these transformations.

PREREQUISITES
  • Understanding of Lorentz transformations
  • Familiarity with the concept of spacetime intervals
  • Knowledge of the Lorentz factor (γ)
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of Lorentz transformations in detail
  • Explore the implications of spacetime interval invariance in special relativity
  • Learn about the physical significance of the Lorentz factor (γ)
  • Investigate examples of spacetime interval calculations in different inertial frames
USEFUL FOR

Students of physics, particularly those studying special relativity, as well as educators and anyone interested in the mathematical foundations of spacetime concepts.

maccyjj
Messages
2
Reaction score
0

Homework Statement


Prove that the spacetime interval
-(ct)^{2} + x^{2} + y^{2} + z^{2}
is invariant.

[/itex]<br /> <h2>Homework Equations</h2><br /> Lorentz transformations<br /> \Deltax&amp;#039; = \gamma(\Deltax-u\Deltat)<br /> \Deltay&amp;#039; = \Deltay<br /> \Deltaz&amp;#039; = \Deltaz<br /> \Deltat&amp;#039; = \gamma(\Deltat-u\Deltax/c^{2})<br /> <br /> <br /> <h2>The Attempt at a Solution</h2><br /> I have tried to prove that \Delta S = \Delta S&amp;#039;<br /> So first I said that \Delta S&amp;#039; = - \Delta (ct&amp;#039;)^{2} + \Delta (x&amp;#039;)^{2} + \Delta (y&amp;#039;)^{2} + \Delta (z&amp;#039;)^{2}<br /> <br /> And inserted all the Lorentz Transformations above into the above formula.<br /> <br /> I end up simplyfying it to get<br /> <br /> \gamma^{2} (x^{2} + u^{2}t^{2} - c^{2}t^{2} - \frac{u^{2}x^{2}}{c^{2}}) + y^{2} + z^{2}<br /> <br /> How does this equal S = - \Delta (ct)^{2} \Delta (x)^{2} + \Delta (y)^{2} + \Delta (z)^{2} ? I can&#039;t see a way to get rid of the extra terms to get this simple function.<br /> <br /> Any help would be really really great!
 
Physics news on Phys.org
If you collect the terms, you'll see that the coefficient of x2 is \gamma^2(1-u^2/c^2). Use the definition of \gamma to simplify that.
 
Oh of course! How did I miss that?

Thank you so much I got it out now!
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
Replies
5
Views
2K
Replies
11
Views
2K
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 54 ·
2
Replies
54
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K