Special Relativity - 2 observers - 2 frames of reference

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SUMMARY

The discussion centers on a problem involving two observers in different frames of reference as described by Einstein's Special Relativity. The first observer in frame S sees two flashes of light, a blue flash followed by a red flash, separated by 2300 m and 5 µs. The second observer in frame S', moving along the x-axis, perceives the red flash first, despite the same spatial separation and time interval. To determine the relative velocity (v) of the moving observer, the Lorentz transformation equations must be applied, specifically using the equation v = Δx/Δt and the Lorentz equation for distance.

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Homework Statement


An observer in frame S standing at the origin observes two flashes of colored light separated spatially by Δx = 2300 m. A blue flash occurs first, followed by a red flash 5 µs later. An observer in S ' moving along the x-axis at speed v relative to S also observes the flashes 5 µs apart and with a separation of 2300 m, but the red flash is observed first. Find the magnitude and direction of v.

Homework Equations


I believe the necessary equation is v = Δx/Δt

The Attempt at a Solution


So I initially thought I would simply have to plug into the above equation Δx = 2300 m and Δt = 5 μs. But now I am realizing that would not give me the velocity of the observer.
To find the velocity of the observer would I have to know the distance he traveled?
And then use Δt = 5x10^-6?
 
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You titled this "special relativity" but you haven't used any formulas from relativity.
 
I figured I could use x = γ(x' + vt') {The lorentz equation for distance}
And then since I am given the spatial separation Δx,
Δx = γ(xo' + vt2' - γ(xo' + vt1'
Then I could solve for v, but that still did not work
 

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