Specific heat and latent heat of fusion

AI Thread Summary
To solve the problem of determining the mass of remaining ice after adding it to tea, the specific heat capacity of water and the latent heat of fusion must be applied. The calculations show that the heat lost by the tea as it cools from 35°C to 15°C is 18,418.4 J. This energy is used to melt the ice and then raise the temperature of the resulting water. The initial calculation incorrectly suggests more mass than started due to not accounting for the temperature increase of the melted ice. Properly including this step will yield the correct mass of remaining ice.
rahndezvous
Messages
2
Reaction score
0
Hi this is my first post and I'm stumped on my last HW problem, so I'm open to suggestions or solutions.

1. A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 35°C. In an attempt to cool the liquid, which has a mass of 220 g, 112 g of ice at 0.0°C is added. At the time at which the temperature of the tea is 15°C, determine the mass of the remaining ice in the jar. Assume the specific heat capacity of the tea to be that of pure liquid water.

_______grams




2. specific heat of water 4186 J/Kg*C
Latent heat of fusion for water 3.33*10^5 J/Kg
Q=Cp*m*/\T
Q=m*Lf
m=Q/Lf



4186 Cp*.22 Kg*20 C=18418.4
18418.4/3.33*10^5 Lf = .5531
.5531*1000=553.1g

Why do I get more than i started with?
 
Physics news on Phys.org
please reply within the next 9.5 hours thanks :)
 
rahndezvous, don't forget that once you've melted the ice, you then need to increase the temperature of the melted ice to 15oC.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggle to understand the concept of the question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

I try to solve a thermodynamics problem on heat transfer
Replies
3
Views
2K
Laten heat of fusion calculation
Replies
13
Views
2K
Mixing water and ice
Replies
12
Views
913
How much ice to cool down this water?
Replies
17
Views
5K
Ice in water question - what is final temperature?
Replies
11
Views
5K
Final temperature after pouring soda into glass with ice....
Replies
5
Views
6K
Thermodynamics adding ice to water problem with latent heat
Replies
1
Views
3K
A wet cloth has been hung out to dry....
Replies
3
Views
2K
Thermodynamics- conservation of heat and energy
Replies
13
Views
2K
What is the Correct Final Temperature in an Ice-Water Heat Transfer Experiment?
Replies
11
Views
3K

Hot Threads

Recent Insights

Back
Top