Specific heat and possibly latent heat too..

[shannon.leigh]

Homework Statement

0.5kg of ice at 0 degrees celcius is mixed with 0.1kg of steam at 100 degrees celcius. what will be the final temperature?

Homework Equations

delta Q= m*c*delta T

and at first i thought delta Q= m*Lf ,but then i changed my mind. . .

The Attempt at a Solution

In my first attempt, i went

Lf*m(of ice) + m*c*(Tf-Ti)(of the now liquid water)=Lv*m(of steam)+ c*m*(Tf-Ti)(of now liquid water)

so 3.34*10^5*0.5 +0.5*4200*(T-0)=2.26*10^6*0.1+4200*0.1*(100-T)
167000+2100T=226000+42000-420T
2520T=435000
T=435000/2520
=172.62
Which is wrong!

so then i got rid of the latent heat and fusion, because i thought they were irrelevant to what i was trying to figure out and went
2100T=42000-420T
T=42000/2520
=16.67
Which is still wrong!

HELP ME PLEASE!

thankyou (:

 

[ehild]

167000+2100T=226000+42000-420T
2520T=435000

Do the simplification again, the RHS is not 435000.

ehild

 

[shannon.leigh]

Are you serious? I just screwed up the calculations?
Damn my terrible skills with a calculator!
And thankyou thankyou thankyou for pointing that out ehild!
I am forever in your debt. :)

 

[ehild]

To tell the truth, there was a mistake in your equation, but you proceeded all right till the last row.

"Lf*m(of ice) + m*c*(Tf-Ti)(of the now liquid water)=Lv*m(of steam)+ c*m*(Tf-Ti)(of now liquid water)"

The red text should be Ti-Tf.

ehild