In an insulated container, 0.50 kg of water at 80 degrees C is mixed with 0.050 kg of ice at -5.0 degrees C. After a while, all the ice melts, leaving only the water. Find the final temperature T_f of the water. The freezing point of water is 0 degrees C. ___________________________________________________ I know that the specific heat of water is 4190 J/(kg*K), the specific heat of ice is 2100 J(kg*K), and that the heat of fusion is 334000 J/kg I also know that the expression for the amount of heat absorbed by ice is 0.05*2100(0-(-5)) The expression for the amount of heat released by water is (0.5)(4190)(T_f-80) The expression for heat of transformation is (334000*0.05) And then I set these Q's that I found to 0. And my answer that I get is 71.78 degrees C. But I have a feeling I am doing something wrong. Any feedback will be awesome.