Specific Heat Capacity of a metal bar placed into water

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SUMMARY

The discussion focuses on calculating the specific heat capacity (shc) of a metal bar placed in water, using the equation C = Eth/mT. The thermal energy gained by water was previously calculated as Eth = 11035.2 J, based on the mass of water (0.150 kg) and its specific heat (4180 J/kg°C). The problem involves determining the metal's shc after it is placed in water, which raises the water's temperature from 4.1 °C to 21.7 °C. The initial temperature of the metal is 96.2 °C, and the relevant equations are established for solving the problem.

PREREQUISITES
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  • Knowledge of temperature change equations
  • Basic algebra for solving equations
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  • Explore examples of specific heat calculations with different materials
  • Investigate the effects of mass and temperature on thermal energy
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lxhull
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Homework Statement
A thermos bottle contains 0.150 kg of water at 4.1 °C. When 9.00 x 10^-2 kg of a metal, initially at 96.2 °C, is put into the water, the temperature of the water rises to 21.7 °C. Calculate the specific heat of the metal
Relevant Equations
C= Eth/mT
Previously solved thermal energy gained by water as
Eth= 0.15(4180)(17.6) = 11035.2 J
Not sure if its relevant
 
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lxhull said:
Not sure if its relevant
It is. How does it relate to the cooling of the metal?
 
haruspex said:
It is. How does it relate to the cooling of the metal?
That's the problem, I don't know. It seems like it can't be part of the equation for the metal's shc because it used the waters shc, so I can't figure it out.
 
lxhull said:
That's the problem, I don't know. It seems like it can't be part of the equation for the metal's shc because it used the waters shc, so I can't figure it out.
Just write the corresponding equation for the metal's change in temperature. Create an unknown for the metal's s.h.
 
lxhull said:
Homework Statement:: A thermos bottle contains 0.150 kg of water at 4.1 °C. When 9.00 x 10^-2 kg of a metal, initially at 96.2 °C, is put into the water, the temperature of the water rises to 21.7 °C. Calculate the specific heat of the metal
Relevant Equations:: C= Eth/mT

Previously solved thermal energy gained by water as
Eth= 0.15(4180)(17.6) = 11035.2 J
Not sure if its relevant
Corrrct so far.
 

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