Specific Heat Capacity of a metal bar placed into water

AI Thread Summary
The discussion focuses on calculating the specific heat capacity (shc) of a metal bar placed in water. The thermal energy gained by the water is calculated as 11035.2 J, using the equation Eth = mCΔT. Participants express uncertainty about how this energy relates to the cooling of the metal. The conversation emphasizes the need to establish an equation for the metal's temperature change and to define its specific heat as an unknown variable. The goal is to accurately determine the metal's specific heat based on the provided data.
lxhull
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Homework Statement
A thermos bottle contains 0.150 kg of water at 4.1 °C. When 9.00 x 10^-2 kg of a metal, initially at 96.2 °C, is put into the water, the temperature of the water rises to 21.7 °C. Calculate the specific heat of the metal
Relevant Equations
C= Eth/mT
Previously solved thermal energy gained by water as
Eth= 0.15(4180)(17.6) = 11035.2 J
Not sure if its relevant
 
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lxhull said:
Not sure if its relevant
It is. How does it relate to the cooling of the metal?
 
haruspex said:
It is. How does it relate to the cooling of the metal?
That's the problem, I don't know. It seems like it can't be part of the equation for the metal's shc because it used the waters shc, so I can't figure it out.
 
lxhull said:
That's the problem, I don't know. It seems like it can't be part of the equation for the metal's shc because it used the waters shc, so I can't figure it out.
Just write the corresponding equation for the metal's change in temperature. Create an unknown for the metal's s.h.
 
lxhull said:
Homework Statement:: A thermos bottle contains 0.150 kg of water at 4.1 °C. When 9.00 x 10^-2 kg of a metal, initially at 96.2 °C, is put into the water, the temperature of the water rises to 21.7 °C. Calculate the specific heat of the metal
Relevant Equations:: C= Eth/mT

Previously solved thermal energy gained by water as
Eth= 0.15(4180)(17.6) = 11035.2 J
Not sure if its relevant
Corrrct so far.
 

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