Speed of electron when kinetic energy given

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To calculate the speed of an electron with a kinetic energy of 6.7 x 10^-19 Joules, the classical kinetic energy formula (1/2 mv^2) can be used effectively. The mass of the electron is required for this calculation. However, if the kinetic energy were significantly higher, such as 100 times larger, the relativistic kinetic energy equation would be necessary for accuracy. For energies 1000 times larger, the relativistic approach is essential. The classical method is suitable for lower energy levels like the one given.
gr3g1
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Hey guys, my teacher saked us to solve for the speed of an electron when the kinetic energy is 6.7*10^-19 Joules

So, I fit in the mass of an electron, and the kinetic energy, and solve for v in the 1/2mv^2 equation??

Thanks a lot
 
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gr3g1 said:
Hey guys, my teacher saked us to solve for the speed of an electron when the kinetic energy is 6.7*10^-19 Joules
So, I fit in the mass of an electron, and the kinetic energy, and solve for v in the 1/2mv^2 equation??
Thanks a lot

well obviously yes...thats one way of doing it!
 
For that energy, the classical kinetic energy equation will work fine. If the energy were 100 times larger, you'd probably need to use the relativistic kinetic energy equation, unless your answer didn't have to be very accurate. If the energy were 1000 times larger, you'd definitely need the relativistic equation.
 
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