Speed of Sound Lab (using slope to find speed of sound)

AI Thread Summary
To find the speed of sound using data from different frequencies, the relationship between frequency and wavelength is crucial, as they are inversely proportional. The speed of sound can be calculated by plotting wavelength against the inverse of frequency (1/f) rather than frequency itself. The slope of this plot will yield the speed of sound, which aligns with the equation λ = v_s/f. The discussion also highlights confusion regarding differentiating the equation for the speed of sound, with a request for clarification on how to approach this differentiation correctly. Understanding these concepts is essential for accurately determining the speed of sound in the lab experiment.
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Homework Statement



If you had data from a lot of different frequencies, how could you use a slope to find the speed of sound? Explain in detail.

Given/Known: So basically we did a lab where we used 3 different tuning forks and hit them over a tube filled with water. We recorded where we heard each node and calculated what half lambda and lamda were in order to find the speed of sound.


Homework Equations



Speed of Sound = frequency * wavelength (lambda)
or
Speed of Sound = 331 + 0.61(T)
T = temperature in celsius (which was 20.2 in our class room)


The Attempt at a Solution



Tried taking the slope of my 3 frequencies (523.2, 1024, 2048 (Hz)) and 3 wavelengths (634.67, 316.00, 152.00 (mm) respectively) in excel. First converted the wavelengths to meters. The slope I got was -2.91. Couldn't figure out any correlation and frankly don't think that's the way to approach the problem.


Solution or any kind of tip very much appreciated. Thanks guys.
 
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The expected relationship between the frequency and wavelength is one of inverse proportion

\lambda = \frac{v_s}{f}.

The speed of sound v_s could be computed from the slope of a fit to the data where you plot \lambda vs. 1/f, instead of \lambda vs. f.
 
fzero said:
The expected relationship between the frequency and wavelength is one of inverse proportion

\lambda = \frac{v_s}{f}.

The speed of sound v_s could be computed from the slope of a fit to the data where you plot \lambda vs. 1/f, instead of \lambda vs. f.

Ok cool. I see how that works and when I got the slope I had a very small percent error so thanks.

Only thing is, my teacher emailed me about the question and told me to differentiate the equation for velocity of sound. To look at dy/dx. I'm not really sure how to do that correctly.

Wouldn't differentiating V=lambda F give you 1 = lambda + F ? Any idea what she wants me to do?
 
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