Speed the generator need to be driven to give an output of 240V D.C?

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To determine the speed required for a generator to produce 240V D.C., the generator's specifications include one pole pair, a square surface area of 6cm x 6cm, a flux of 18mWb, and four commutator segments. The formula F = (P * N) / 120 is suggested, but there is uncertainty regarding the number of turns (loops) in the generator. A guess of 3000 RPM is proposed for the calculation, leading to a result of 50, but clarification on the number of loops is needed for accuracy. The discussion highlights the importance of knowing the number of turns to finalize the speed calculation. Understanding these parameters is crucial for achieving the desired output voltage.
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1. The question is "what speed will the generator need to be driven to give an output of 240V D.C?" the generator is constructed using one pole pair having a sq surface of 6cm x 6cm and produces a flux of 18mWb. It has 4 commutator segments.
2. Possibly F = (P * N) / 120? I am not sure
3. F = (P * N) / 120 = (2*3000(dont know the number of turns this was a guess)?)/120 = 50
 
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How many loops does it have? 1 or 2?
 

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