Splitting field of a polynomial over a finite field

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Homework Statement


Assume F is a field of size p^r, with p prime, and assume f \in F[x] is an irreducible polynomial with degree n (with both r and n positive).

Show that a splitting field for f over F is F[x]/(f).

Homework Equations


Not sure.

The Attempt at a Solution


I know from Kronecker's theorem that f has a root in some extension field of F, but I don't know that this root is necessarily in F[x]/(f). If I could obtain this, I could use the fact that finite extensions of finite fields are Galois, therefore normal (and separable), so f splits in F[x]/(f).
I also know that finite extensions of finite fields are simple, so F[x]/(f) \cong F(\alpha) for some \alpha. Then the substitution homomorphism (g \rightarrow g(\alpha)) might help, if I knew that \alpha is a root of f.

Thanks in advance.
 
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I think you're thinking too hard. You want to find some polynomial expression in x that you can plug into f to get something that is divisible by f(x), right?
 
I've got it, thanks.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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