GoGoGadget
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Homework Statement
Draw a picture of a spring connected over pulleys to two hanging objects of equal
weight at equilibrium. Determine the relationship of forces among each individual object, then find a final equation that describes the overall relationship of the objects to one another.
Homework Equations
F = ma
Hooke's law for springs:
Fs = -kx
The Attempt at a Solution
Body-diagram of the model described above is attached to this post. I know the equation for describing the force of a spring is by Hooke's Law:
Fs = -kx
Forces acting on just the spring (for both directions):
Fy = may = 0
Fx = T-kx = max
Forces acting on M1 & M2:
Fx = max = 0
Fy = T-mg = may = 0
T-mg = 0
T = mg
Relationship of spring with M1 & M2:
So if T = mg, we can substitute T for mg in the equation. I know we need to subtitute the equation so the relationship can be determined on one component and for this, I did it for the x axis. Here's what I have so far:
Fx = max
-kx-M1-M2=max
From here, I'm not sure what to do. On the one hand, I know that the masses on both ends of the spring on going to keep extending the spring out. And I know that the masses are going to be proportional to one another as the spring continues to extend. However, I'm not sure what to make of the max portion of the equation. I know that M1 and M2 are equivalent to the force of mg but when the m in the mzx is divided, that would cancel out the "m" variables of M1 and M2. Any help from here is appreciated.