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The problem is to find out how much lower will the end of the spring be when it reaches its new equilibrium position? One end of the spring is fixed to the ceiling and the other is attached to a 1 kg mass and the spring constant is 325 N/m.

I read this problem from text. In order to find the new equilibrium position, we must use Hooke's law, right? But, I find that the initial length is missing.

Given quantities:

F = m * a = 1 kg * 9.81 m/s2

K = 325 N/m

Unknown quantities:

l = ? (to be calculated)

lo (initial equilibrium) = ? (not given in the problem)

How can i go about to find l ( new equilibrium)? Any one please help.

regards,

vanchin

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# Spring Mechanics

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