Springs and simple harmonic motion

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SUMMARY

The discussion centers on calculating the new period of a mass-spring system when the mass is reduced to one-third of its initial value. The relevant equation is T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. By substituting m with m/3, the new period can be determined, resulting in a value of approximately 1.73 seconds. This demonstrates the inverse relationship between mass and the period in simple harmonic motion.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with the mass-spring system dynamics
  • Knowledge of the formula T = 2π√(m/k)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the effects of varying spring constants on oscillation periods
  • Explore the concept of damping in simple harmonic motion
  • Learn about energy conservation in mass-spring systems
  • Investigate the relationship between frequency and period in oscillatory motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators teaching concepts related to simple harmonic motion and mass-spring systems.

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Homework Statement


If the initial period is 3.0 s and the mass is reduced to 1/3 of its initial value, what is the new period?

Homework Equations



Possibly T=2pi*squareroot(m/k)

The Attempt at a Solution


The solution is something close to 1.73. I have no idea what equation to use, even. Any assistance would be appreciated.
 
Last edited:
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You have the right equation, just use it. 3s=T=2pi*sqrt(m/k). Now change m->m/3. By what factor does T change?
 
Yes! Thank you!
 

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