Engineering What Are the Initial and Steady State Values in an SPST Switched RLC Circuit?

AI Thread Summary
In an SPST switched RLC circuit, at t=0-, the capacitor behaves as an open circuit and the inductor as a short circuit, resulting in vC(0-) = 12V and iL(0-) = 0. At t=0, the capacitor acts as a voltage source and the inductor as a current source of 0A, leading to iC(0) = -3A and vL(0) = 12V. At steady state (t=infinity), the capacitor again acts as an open circuit and the inductor as a short circuit, yielding vC(infinity) = 0V and iL(infinity) = 4A. The calculations presented are confirmed to be correct. Understanding these initial and steady state values is crucial for analyzing RLC circuits.
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Homework Statement


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SPST switch closes at t=0. Find vC(0-) and iL(0-), iC(0) and vL(0), and vC(infinity) and iL(infinity).

Homework Equations


The Attempt at a Solution


kind of basic circuit, i know, but i just wanted to check my answers in case i did something wrong.

At t=0- : capacitor acts like open circuit, inductor like short circuit. also there no closed loops, so there's no current. vC(0-)=V(s)=12V, and iL(0-)=0.

at t=0: capaciator behaves like voltage source, inductor like current source of 0A. so would iC(0) be -3A? and vL(0)=12V.

at t=infinity: capacitor acts like open circuit, inductor like short circuit. vC(infinity)=0V, and iL(infinity)=4A.
 
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Looks right to me
 
anyone else?? did i do this right?
 
asdf12312 said:
anyone else?? did i do this right?

Yes you did.
 

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