Standing Sound Waves: Wavelengths in 121 cm Tube - SOLVED

AI Thread Summary
The discussion addresses the calculation of the three longest wavelengths for standing sound waves in a 121 cm tube, both open at both ends and open at one end while closed at the other. For a tube open at both ends, the wavelength is calculated using the formula λ = 2L/m, where m represents the mode number. In contrast, for a tube open at one end and closed at the other, the formula is λ = 4L/m, with m taking only odd values. The clarification provided indicates that the three longest wavelengths correspond to the three lowest modes, confirming the initial assumption. This understanding resolves the confusion regarding the calculation of wavelengths in different tube configurations.
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[SOLVED] Standing Sound Waves

What are the three longest wavelengths for standing sound waves in a 121 cm long tube that is (a) open at both ends and (b) open at one end, closed at the other?


the wavelength equation that i used for open-open was \lambda= 2L/m; where m is the number of modes (m=1,2,3,4...)

and then for open-closed \lambda= 4L/m; where m is the number of modes (m=1,3,5,7...)

so i have the length, but the one question that i have about this problem is could i start with the lowest number of modes, but if that is true then why ask for the three longest wavelength, so i am kind of lost if anyone could give me a clue on what to do

thanks in advance
 
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The three longest wavelengths correspond to the three lowest modes.
 
oh ok, that was exactly what i thought it was thanks
 
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