Static Equilibrium On a Beam Question

AI Thread Summary
When the beam is lifted and repositioned slightly to the left, its stability depends on the forces acting on it, particularly the static friction force. If the beam is placed carefully and is not in motion when released, it may remain stationary, provided the static friction can counteract any potential slipping. However, if the repositioning alters the balance of forces beyond the maximum static friction, the beam may begin to slip. The outcome hinges on the relationship between the beam's weight, the angle of inclination, and the coefficient of static friction. Thus, careful placement does not guarantee stability if the forces are unbalanced.
hardygirl989
Messages
20
Reaction score
0

Homework Statement



A uniform beam of length L and mass m shown in the figure below is inclined at an angle of θ to the horizontal. Its upper end is connected to a wall by a rope, and its lower end rests on a rough horizontal surface. The coefficient of static friction between the beam and surface is μs. Assume the angle θ is such that the static friction force is at its maximum value.

(e) What happens if the beam is lifted upward and its base is placed back on the ground slightly to the left of its position in the figure above?

Picture: http://www.webassign.net/serpse8/12-p-016.gif

Homework Equations



N/A

The Attempt at a Solution



I figure out most of the question, but I am having trouble with part e. I guess I just need clarification on the vocabulary. Would the beeam slip since it does move to the left or does it stay stationary because the person moved it to the left? Can anyone help? Thanks.
 
Physics news on Phys.org
Assume that the person places it carefully so that it is not in motion before he let's go. The question then is, will the beam start to slip in its new position or will it remain in place?
 
If the person places it so carefully, then is it safe to assume that the beam will remain stationary?
 
hardygirl989 said:
If the person places it so carefully, then is it safe to assume that the beam will remain stationary?

Nope. That will depend upon the sum of the forces acting.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top