Statics problem. Cable with distributed load

AI Thread Summary
The discussion revolves around solving a statics problem involving a cable with a distributed load. The original poster seeks assistance in determining the correct equations to use, specifically mentioning T=((T_o)^(2)+(wy)^(2))^(1/2) but feeling unsure about their application. Suggestions include drawing a free body diagram to visualize the forces acting on the cable, noting that the forces must be in equilibrium and can be analyzed graphically. There is frustration expressed regarding the timing of the assignment, as the professor recently covered the derivation in class. Overall, the conversation emphasizes the importance of understanding force equilibrium and graphical methods in solving the problem.
ThewyBenner
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20161101_101911.jpg

Homework Statement


can someone please help and explain to me how to do this problem? all the data is in the picture above.

Homework Equations


i am not entirely sure which equations i should use. i know one possible equation is T=((T_o)^(2)+(wy)^(2))^(1/2)

The Attempt at a Solution


with the one equation that i know, i can say that point 1 is not the bottom of the parabola.
past that i need help
Any help would be appreciated
i have been stuck for about a day and a half and just don't know where to start.

Thank you so much
 
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I haven't tried to solve it all (not sure I can) but try drawing a free body diagram for the rope showing the horizontal forces. I think it's possible to work out the angle the rope makes at the bottom if that helps.
 
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You know the forces at the ends of the cable. You know those forces are tangential to the cable ends. You know the drag. That makes 3 forces. If they are in equilibrium they must all meet at one point. You don't have enough information about the cable self-weight to take account of that. Can you do it graphically with a triangle of forces?
 
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thanks both of you for the help. my proffessor just walked through the derivation today in class. . . I don't know why he assiNed the problem so early. . .
thanks again
 

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