Steel mass attached to the ceiling, maximum height gain if it is hit

Click For Summary

Homework Help Overview

The problem involves a 275 kg steel mass suspended from the ceiling by a cable, which is struck horizontally, imparting a speed of 1.75 m/s. The objective is to determine the maximum height gain of the mass after the collision, assuming no friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy to relate kinetic energy and gravitational potential energy. There is uncertainty regarding the interpretation of the motion of the mass and the reference point for height measurement.

Discussion Status

Some participants have provided guidance on using conservation of energy principles. There is a recognition of a calculation error regarding the velocity squared, which led to a revised height calculation. Multiple interpretations of the problem setup are being explored.

Contextual Notes

The original poster notes the absence of an angle in the problem statement and the lack of information about the height from the ground, which influences the reference point for height calculations.

needingtoknow
Messages
160
Reaction score
0

Homework Statement


A 275 KG steel mass is held by a long cable to the ceiling. Daniel hits the steel mass horizontally and gives it a horizontal speed of 1.75 m/s. Assuming there is no friction, determine the maximum height gain, in centimetres, of the steel mass after the collision.


Homework Equations


W = Fd
E = 1/2mv^2
Eg = mgh


The Attempt at a Solution



These are the only three equations given in the question, and no angle is given in the question so how would I calculate the height at which the pendulum moves (if the question is suggesting that the steel block is moving in a pendulum fashion which I am not entirely sure of)
 
Physics news on Phys.org
Try conservation of energy. When it is at its highest point, the mass is not moving so all of its initial kinetic energy has been converted into gravitational potential energy.
 
All right so using the law of conservation of energy here is what I got.
1/2mv^2 + mgh = 1/2mv^2 + mgh
1/2(275)(1.75) + 0 = 0 + (275)(9.8)h
240.625/2695 = h
h = 8.9 cm but the answer is 15.6 cm
 
Oh and I used the rest position of the steel block as my reference point because they didnt give the distance off of the ground.
 
Don't forget to square the velocity.
 
Oh never mind I got the answer. Thanks for the helps HS-Scientist!
 
Yeah just realized that! I got 15.6 cm after I fixed that.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
6
Views
8K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K