Stepped Pulley: Angular and Linear Acceleration

AI Thread Summary
A stepped pulley consists of concentric disks with varying radii, used to analyze angular and linear acceleration. The system includes two masses attached to different radii, requiring the application of torque and Newton's second law for rotational motion. The discussion highlights confusion regarding the initial rest state of the pulley and the relationship between angular speed and linear acceleration. Key equations involve torque (τ = Iα) and the linear relationship (v = rω), emphasizing the need to determine angular acceleration first. The conversation concludes with a focus on applying fundamental physics principles to solve the problem effectively.
robert6774
Messages
5
Reaction score
0
A stepped pulley is essentially a system of connected cocentric disks that have different radii. A stepped pulley (I= 2.0 kg*m^2) is placed on a frictionless axle and then strings are attached to two radii of 20 and 50 cm. The other ends of the strings are attached to a 2.0 and 1.0 kg mass respectively. Determine the angular acceleration of the pulley and the linear accelerations of the two masses.

I= 2.0 kg*m^2
r1= 50 cm
r2= 20 cm
m1= 1.0 kg
m2= 2.0 kg
w1= 0
w2= ?

I think I'm confusing the concept of the pulley starting at rest (so w1= 0) and the final angular speed (w2) of the rotating pulley with the fact that there are two different radii to be used in the same equation for the same pulley.

I'm pretty sure v= rw will come into play at some point but I need to find the angular speed in order to find the angular acceleration. And where the heck does time fit into all this?

I've also considered finding the linear accelerations and working the other way around but again I'm not sure how to look at this.

I've winged a couple ideas using the conservation of angular momentum and the conservation of angular kinetic energy but it doesn't make sense. Where do I start and how do look at/approach this problem?
 
Physics news on Phys.org
Last edited by a moderator:
Thank you tiny-tim for your help. I've just figured out how to use the Latex symbols, that should make my equations easier to read. The other Latex stuff is a bit more complicated, don't know if I'll need it.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top