Stokes Law, Viscosity. (very simple)

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The discussion centers on calculating the viscosity of glycerol using the equation V = [2r^2 (p – σ) g] / 9η, where various parameters such as density of steel balls (p), density of glycerol (σ), and gravitational acceleration (g) are considered. The user derived the equation η = 129360r^2 / 9V but encountered an issue where viscosity appears to decrease with a smaller radius. This led to confusion, as viscosity is typically regarded as a constant at a given temperature. It was clarified that while viscosity remains constant, the coefficient of drag varies with size, indicating that the observed changes in viscosity calculations may stem from the influence of drag forces and momentum exchange, rather than an error in the viscosity value itself.
mr-tom
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I'm trying to find the viscosity of some glycerol that we dropped various steel balls down using the equation:

V = [2r^2 (p – σ) g] / 9η

I put in these values:
p = 7800 kg m-3
σ = 1200 kg m-3
g = 9.8 m s-2

And ended up with the equation. η = 129360r^2 / 9V

My problem is that I thought viscosity is a constant. When I put my values in the viscosity decreases as radius decreases.
 
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Ok thanks, so i must've made a mistake somewhere...
 
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