Strange physics question involving no constants and all variables.

AI Thread Summary
The discussion revolves around a physics homework problem involving the time derivative of acceleration, denoted as "K." Participants emphasize that displacement, velocity, and acceleration are all functions of time, suggesting that time is the sole variable to consider. To find the functions a(t), v(t), and d(t), they recommend using the Fundamental Theorem of Calculus, specifically integrating K with respect to time. Initial hints indicate that the relationship between acceleration and K can be expressed through integration, leading to a(t) = K^2/2 + C. The conversation highlights the challenge of working with variables instead of numerical values, but provides guidance on approaching the problem mathematically.
TexasCow
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Homework Statement


"K" is the time derivative of acceleration. Assume initial conditions of Ao, Vo, and Do.("o"=initial).

Find:
a(t):
v(t):
d(t):

Show that:
af^2=ao^2+2J(Vf-Vo)


Homework Equations



I'm honestly lost on this one..I don't know where to start. I could probably do it with numbers but clueless with variables!



The Attempt at a Solution

 
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Hey,

Remember that what is common between the: displacement, velocity, and acceleration functions; are that they're all functions of time, indicating that t is your only variable.

Therefore, consider the following,

<br /> {\frac{d}{dt}}{\left[a(t)\right]} = K<br />

So, if the derivative with respect to t was taken to get K, how do you get back a(t)?

Once you figure that out repeat for v(t) and d(t).

Thanks,

-PFStudent
 
Last edited:
Hint: Use the Fundamental Theorem of Calculus.
 
Integral maybe?
 
TexasCow said:
Integral maybe?

Hey,

Yes. To get you started here is how it looks,

<br /> {a(t)} = {\int_{}^{}}{K}{dt}<br />

Thanks,

-PFStudent
 
Well we haven't gotten there in calc yet but I'm sure I can find out how to do that online somewhere.
 
Hint 1: K is the same as K^1
Hint 2: a(t) = K^2/2 + C
 
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