Hey there, I have been studying for my physics final coming up and I am constantly getting stuck on the stuff that we started at the beggining of the year. Such as this question: A 6 kg object is projected directly upwards with an initial speed of 15 m/s. This object experiences an average air resistance force of 24 N. What is the maximum height reached by this object? I have no idea how to solve it. If it weren't for the air resistance I would prolly go something along the lines of: KE = PE (1/2)mv^2 = mgh h = [(1/2)v^2] / g I also thought of going like Fnet = ma 24 N = (6 kg)(a) a = 4 m/s So the total acceleration would be: -9.8 m/s/s + 4 m/s/s which is -5.8 m/s/s Then I used kinematics such as Vf^2 = Vo^2 + 2ad (0m/s)^2 = (15 m/s)^2 + 2(-5.8m/s/s)d d = 19.3 m That is one of the answers but it is wrong as the answer is 8.2m. So I have no idea how to solve questions like these, so I am coming here to ask for help. Thank you.