Surface Charge Distrib on Plane

AI Thread Summary
The discussion focuses on finding the electric potential due to a charged infinite plane with a surface charge density defined by σ = σ₀ sin(αx) sin(βy). The initial approach involves using Gauss's Law to determine the electric field, but the complexity of the non-uniform charge distribution complicates this method. Instead, the potential can be derived from the relationship between the electric field and the potential, specifically using the equation E = -∇V. By recognizing that the electric field is directed in the z-direction, the potential can be calculated by integrating the electric field with respect to z. This approach provides a pathway to solve the problem despite the challenges posed by the infinite plane.
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Homework Statement


The plane z = 0 is charged to a density \sigma = \sigma_0 sin(\alpha x) sin(\beta y)

Find the potential.

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The Attempt at a Solution



Well I first thing I would normally do is use Gauss's Law to find E
E = \frac{\sigma}{2e0} for an infinite plane, however in this case I don't appear to be able to just plug it in like that.

My next thought would be to find the total charge Q, but how does one do that when the plane is infinite?
 
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I think you might have to use \vec{E}=-\vec{\nabla}.V, where \vec{\nabla}.V=\frac{dV}{dx}\hat{x}+\frac{dV}{dy}\hat{y}+\frac{dV}{dz}\hat{z}.

So if you know the electric field acts in the z direction you can say that \frac{dV}{dz}=\frac{-\sigma}{2\epsilon_0}, so you can integrate w.r.t to z to find the potential. I think that's how you would do it anyway, hope this helps.
 
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