- #1
transgalactic
- 1,395
- 0
i added the question and how i tried to solve it in the link
http://img146.imageshack.us/my.php?image=img8217ix2.jpg
http://img146.imageshack.us/my.php?image=img8217ix2.jpg
i tried to use this formula but i didnt understand how the "n" member
works
To solve a tailor series question, you first need to understand the concept of tailor series and its formula. Then, you need to identify the function and its derivatives. After that, you can use the tailor series formula to find the coefficients and plug them into the formula to get the final solution.
The formula for tailor series is f(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)^2/2! + f'''(a)(x-a)^3/3! + ... where f(a) is the value of the function at a, f'(a) is the first derivative of the function at a, and so on.
Some common mistakes when solving a tailor series question include using the wrong formula, not properly identifying the function and its derivatives, and making calculation errors while finding the coefficients. It is important to double check all the steps and calculations to avoid these mistakes.
Simplifying the tailor series before plugging in values is very important as it helps in reducing the chances of making errors and also makes the calculation process easier and faster. It also helps in understanding the solution better.
Yes, tailor series can be used to approximate any function as long as the function is smooth and has enough derivatives at the point of approximation. However, for some functions, the tailor series may not converge to the exact solution and may only be an approximation.