Tell me the fourmla for displacement

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Homework Help Overview

The discussion revolves around calculating displacement in a physics context, specifically involving initial and final velocities. The original poster seeks clarification on the formula for displacement while providing a scenario involving a squirrel's velocity changes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for additional information to accurately determine displacement, questioning the assumptions regarding acceleration and time. Some suggest that the displacement could be negative based on the final velocity being less than the initial velocity.

Discussion Status

There is an ongoing exploration of the problem with participants offering different formulas for displacement and emphasizing the necessity of more data. While some guidance has been provided regarding the formulas, there is no explicit consensus on how to proceed without further information.

Contextual Notes

Participants note that acceleration and time are critical variables that are currently missing from the original poster's scenario, which affects the ability to calculate displacement accurately.

killer22
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okay i have a question.
if a squirrel is at 0 on inital velocity and then is at -2 at final velocity.then what is its displacement?
And i would appreciate it if someone can tell me the fourmla for displacement.:smile:
 
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you need to give a lot more info to be able to do this problem

disp= x_o+v_0*t+1/2at^2
 


I think you would have a negative displacement you instead of going forwards went backwards your displacement would be 2. I think I have problems with physics so...
 


Like mathmike said, you need to give a lot more information so an accurate displacement can be given, unless you are searching for displacement as a function of acceleration/time etc.

Using:

[tex]s=ut+\frac{1}{2}at^{2}[/tex] (1)

or

[tex]v^{2}=u^{2}+2as[/tex]
Hence, [tex]s=\frac{v^{2}-u^{2}}{2a}[/tex] (2)

where,
s=displacement
u=initial velocity
t=time
a=acceleration

Using the information you have given, formula (1) can be simplified to:

[tex]s=\frac{1}{2}at^{2}[/tex]

and formula (2) can be simplified to:

[tex]s=\frac{2}{a}[/tex]

It is obvious you will at least need acceleration to find the displacement, and yes, the displacement will be negative since your final velocity (v) is negative.
 

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