Temperature and Harmonic Functions

jgens
Gold Member
Messages
1,575
Reaction score
50

Homework Statement



Find the temperature of the semi-circular plate of radius 1 with the following boundary temperatures: T=0 along the semi-circle, T=0 along (-1,0), and T=1 along (0,1).

Homework Equations



N/A

The Attempt at a Solution



Well, the author of the text has already noted that temperature functions are harmonic, so I'm looking for a harmonic function here. I've already tried a number of stock examples (like taking the real and imaginary parts of log(z)), but I can't seem to get anything to work. Can someone give me a hint to get me working in the right direction here? Thanks!
 
Physics news on Phys.org
This puzzles me as when dealing with temperature you use the diffusion equations which is parabolic, and looks like:
<br /> \frac{\partial T}{\partial t}=\frac{1}{\alpha}\frac{\partial^{2}T}{\partial x^{2}}<br />
These don't define harmonic functions in general. What equation is he using here?
 
The text we're using (Lang's Complex Analysis text) just says that temperature functions are harmonic. So, I'm guessing we're supposed to find a harmonic equation modeling the temperature of the plate, but I can't think of any trivial examples that make it work out. It's not a physics text, so I wouldn't be surprised if it grossly simplified the physics behind temperature.
 
Conformal transformations in the answer. Transform a semi-circle into a region where you know you can solve the equation and then it should be easy from there.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top