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wlvanbesien
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At a fabrication plant, a hot metal forging has a mass of 76 kg and a specific heat capacity of 430 J/(kg · °C). To harden it, the forging is immersed in 710 kg of oil that has a temperature of 32°C and a specific heat capacity of 2900 J/(kg · °C). The final temperature of the oil and forging at thermal equilibrium is 46°C. Assuming that heat flows only between the forging and the oil, determine the initial temperature of the forging.
(the sub 1 refers to the metal, the o refers to the oil)
what I assumed I would do for this is say:
[tex]m_{1}c_{1}T_{1}=m_{o}c_{o}(\Delta T_{o} - 46^o C)[/tex]
then
[tex]T_{1}=\frac{m_{o}c_{o}(\Delta T_{o} - 46^o C)}{m_{1}c_{1}}[/tex]
That, unfortunately, is wrong...
any help would be great ... this is due in an hour.
I also have a problem with this question:
A precious-stone dealer wishes to find the specific heat capacity of a 0.032 kg gemstone. The specimen is heated to 95.0°C and then placed in a 0.10 kg copper vessel that contains 0.083 kg of water at equilibrium at 25.0°C. The loss of heat to the external environment is negligible. When equilibrium is established, the temperature is 28.5°C. What is the specific heat capacity of the specimen?
for this one i used the same
[tex]c_{1}m_{1}\Delta T_{1}=c_{2}m_{2}\Delta T_{2}[/tex]
formula, but it was wrong again... Am I even using the correct formula? Thanks!
(the sub 1 refers to the metal, the o refers to the oil)
what I assumed I would do for this is say:
[tex]m_{1}c_{1}T_{1}=m_{o}c_{o}(\Delta T_{o} - 46^o C)[/tex]
then
[tex]T_{1}=\frac{m_{o}c_{o}(\Delta T_{o} - 46^o C)}{m_{1}c_{1}}[/tex]
That, unfortunately, is wrong...
any help would be great ... this is due in an hour.
I also have a problem with this question:
A precious-stone dealer wishes to find the specific heat capacity of a 0.032 kg gemstone. The specimen is heated to 95.0°C and then placed in a 0.10 kg copper vessel that contains 0.083 kg of water at equilibrium at 25.0°C. The loss of heat to the external environment is negligible. When equilibrium is established, the temperature is 28.5°C. What is the specific heat capacity of the specimen?
for this one i used the same
[tex]c_{1}m_{1}\Delta T_{1}=c_{2}m_{2}\Delta T_{2}[/tex]
formula, but it was wrong again... Am I even using the correct formula? Thanks!
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