Temperature of a thin bulb filament

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The discussion revolves around calculating the temperature of a thin bulb filament based on its length (L) and radius (r), with the derived relationship being T ~ r^(1/4) * L^(-1/2). The Stefan-Boltzmann law is referenced, emphasizing that it relates to the power radiated by the filament, which is influenced by both the filament's dimensions and the Joule-Lenz law. Participants clarify that L and r affect the radiated power and surface area, impacting the power density. The conversation highlights the importance of using the correct forum for homework-related questions. The thread concludes with a reminder about the utility of following a homework template for clarity.
Baibhab Bose
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In my assignment question, the length L and radius r is given and asked to find out how the Temperature of a thin bulb filament which depends on those two parameters. and the answer is r^(1/4)*L^(-1/2). I can't figure out how. Which relation is involved?
 
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For constant voltage at ends,
T~r1/4L-1/2
Use Stefan-Boltzmann law and neglect ambient temperature.
 
trurle said:
For constant voltage at ends,
T~r1/4L-1/2
Use Stefan-Boltzmann law and neglect ambient temperature.
I still can't get this. Stefan Boltzmann law states only Power radiated= σT^4. But where do we get the L and r?
 
Baibhab Bose said:
I still can't get this. Stefan Boltzmann law states only Power radiated= σT^4. But where do we get the L and r?
L and R affect both radiated power (by Joule-Lenz law) and surface area of filament which affect radiated power density
 
Okay! Got it! Thank you so much!
 
This question should have been asked in the homework forum. Filling out the homework template would have been useful.

Thread closed,
 
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