(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

1.5 is a typical walking speed.

At what temperature would nitrogen molecules have an rms speed of 1.5 ?

2. Relevant equations

V=(3*K_b*T/m)^.5

V is the rms speed

K_b is Boltzmann's constant

T is temp in kelvin

m is mass

3. The attempt at a solution

I am going to make the foolish assumption that when they mean mass, they mean the mass of one nitrogen molecule. So the mass of a proton and a neutron is 1.67E-27kg and the mass of an electron is 9.11E-31kg. One nitrogen atom has 7 protons, 7 neutrons and 7 electrons and multiply that by two because of the second nitrogen atom. So ((1.67E-27)(14)+(7)(9.11E-32))(2)=4.677E-26 kg.

Now I rearrange my equation to solve for T and plug in.

mV^2/(3*K_b)=T

(4.677E-26)(1.5)^2/(3*K_b) = .0025 kelvin

Am I close?

Thanks!

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# Homework Help: Temperature of nitrogen

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