Temperature of Water in a Moving Plane

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Discussion Overview

The discussion revolves around the relationship between translational kinetic energy and temperature in the context of a cup of water placed in a fast-moving jet. Participants explore why the temperature of the water remains unchanged despite an increase in kinetic energy due to the jet's velocity.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions why the temperature of water does not change in a moving jet, despite the translational kinetic energy being expressed as 3/2 RT.
  • Another participant suggests that the cup and surrounding air are stationary relative to the vehicle, which may explain the observed temperature consistency.
  • A participant proposes that the explanation could be framed in terms of internal energy.
  • Another contribution discusses the internal kinetic energy of the cup relative to its center of mass, indicating that total kinetic energy includes both internal and external components.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, with multiple viewpoints presented regarding the relationship between kinetic energy and temperature in this scenario.

Contextual Notes

Participants reference different frames of reference (the vehicle versus the airport) and the concept of internal energy, indicating potential complexities in the definitions and assumptions involved.

eranium
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Hello people,

i have been wondering if translational K.E = 3/2 RT, where T is the temperature, why is it that when we place a cup of water in a fast moving jet, the Temperature still remains the same, even though the K.E of the cup of water increases (due to the velocity of the jet)

would appreciate if someone help clear some doubts,
thanks in advance!
 
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I assume it's because the cup, and the surrounding air, are stationary relative to the vehicle.
 
is it possible to explain this in terms of internal energy?
 
The internal K.E. of the cup is T3/2 R relative to its own center of mass.

Relative to the airport, Total K.E. = (3/2)TR + (1/2)mv^2. (v being the speed of the center of mass).
 

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