Tension at the middle of a string of known mass

AI Thread Summary
To find the tension at the midpoint of a string connecting two 15kg blocks with a 2kg mass, a force of 66N is applied to the right block on a frictionless surface. The relevant equations include Newton's second law and kinematic principles. A free body diagram for each mass is essential for visualizing the forces acting on the system. The tension can be calculated by analyzing the forces and acceleration of the entire system. Understanding these concepts will facilitate solving the problem effectively.
natnat_nuts
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Homework Statement



How can i get the tension in the midpoint of a string of mass 2kg that connects two blocks of mass 15kg each if i applied a force 66N to the block on the right to drag the system across a frictionless surface?

Homework Equations





The Attempt at a Solution

 
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Hi natnat_nuts, welcome to PF.
what are the relevant equations you have to use to solve this problem?
Show your attempts. Draw the free body diagram of each mass.
 
my teacher gave us nothing in particular . . . that's why it's difficult. we could use Newton's second law, kinematics, work-kinetic energy theorem etc since we have discussed those already.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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