Tension Problems Given Two Weights

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Homework Help Overview

The discussion revolves around a physics problem involving two hanging paint buckets, each with a mass of 3.2 kg, connected by massless cords. The original poster seeks to determine the tension in the cords under two scenarios: when the buckets are at rest and when they are being accelerated upward at 1.6 m/s².

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate the tension in the cords using force balance equations for both scenarios. Some participants question the assumptions made regarding the forces acting on the buckets, particularly in the context of acceleration.

Discussion Status

Participants are exploring the calculations related to the tension in the cords, with some guidance provided regarding the need to consider gravitational forces even when the buckets are accelerating. There is recognition of the original poster's confusion, but no explicit consensus has been reached on the correct approach.

Contextual Notes

There is mention of potential calculation errors and the need for clarity on how forces interact when the system is in motion versus at rest. The original poster expresses uncertainty about their understanding of the problem.

yandereni
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Homework Statement


One 3.2kg paint bucket(B) is hanging by a massless cord from another 3.2kg paint bucket(A), also hanging by a massless cord.
a.) if the buckets are at rest, what is the tension in each cord?
b.) if the two buckets are pulled upward with an acceleration of 1.6m/s2 by the upper cord, calculate the tension in each cord.

this is one of the problems I am confused with actually

Homework Equations


all i can make out is :
1. finding the tension when at rest
box[a] ==> FtensA = (agrav)(mA) + Ftens B
box ==> FtensB = (agrav)(mB)
2. finding the tension force given the acceleration 1.6m/s2
box[a]==>FtensA = mAaA +FtensB
box==>FtensB = mBaB

The Attempt at a Solution



I tried to solve for the tension when at rest and this is how it turned out:
FtensA = (9.8m/s2)(3.2kg) + FtensB
= 31.6N + 31.6N
= 63.2N
FtensB = (9.8m/s2)(3.2kg)
= 31.6N

Then I tried to solve for the tension given the acceleration
FtensA = (1.6m/s2)(3.2) + FtensB
= 5.12N + 5.12N
= 10.24N
FtensB = (1.6m/s2)(3.2kg)
= 10.24N

I really think that I'm wrong in here because its really confusing...Thanks In Advance! :)

<<Moderator note: Edited for formatting.>>
 
Last edited by a moderator:
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Part A you did correctly(though your calculation is a bit off). But when you take the tension of the cord given the new upward acceleration, remember that the first tension that you calculated doesn't go away. So how do you think you should approach part B with that in mind?
 
yandereni said:
FtensA = (agrav)(mA) + Ftens B

In this case, (agrav) is the gravitational acceleration which means that mA(agrav) is the gravitational force acting on the bucket A. Since the bucket is at rest, the equation is a force balance for bucket A (all forces must sum to zero).

yandereni said:
FtensA = mAaA +FtensB
The gravitational force does not disappear just because you are accelerating the bucket. Also, since the buckets are now being accelerated, the forces should not add to zero, but perhaps one of Newton's laws can tell you what it should sum to?
 
Oh, now it all makes sense. I forgot the part where the bucket is at rest. Thank you so much! I understand everything now. :)
 

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