Tensor Analysis: Solving Isotropic Second-Rank Tensors in 3-D Space

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Homework Statement


I am having trouble solving this problem. From an analysis of the behavior of a general second-rank tensor under 90 degree and 180 degree rotations about the coordinate axes, show that an isotropic second-rank tensor in 3-D space must be a multiplier of delta ij.


Homework Equations





The Attempt at a Solution

 
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Well, what does "isotropic" mean here? And how does a tensor change under rotations?
For this problem you don't really need to look at general rotations: rotation by 90 degrees changes x to y and y to -x. Rotation by 180 degrees changes x to -x and y to -y.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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