The angle of the first order diffraction

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SUMMARY

The angle of the first order diffraction (m=1) for X-rays diffracting from a crystal with an atomic plane spacing of 0.175 nm is calculated to be 69 degrees. The second order diffraction (m=2) occurs at 45 degrees, confirming that higher order reflections correspond to larger Bragg angles. The relationship between the order of diffraction and the angle is established through the equation Δr=2dcosθm, where m represents the order of diffraction, d is the spacing between atomic planes, and θm is the diffraction angle.

PREREQUISITES
  • Understanding of Bragg's Law
  • Familiarity with X-ray diffraction principles
  • Knowledge of trigonometric functions in physics
  • Basic concepts of crystal structure and atomic spacing
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  • Explore the calculation of diffraction angles for higher order reflections
  • Learn about the significance of atomic plane spacing in material science
  • Investigate the role of X-ray diffraction in determining crystal structures
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Students in physics and materials science, researchers in crystallography, and professionals working with X-ray diffraction techniques will benefit from this discussion.

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Homework Statement



What is the angle of the first order diffraction, m=1, when X-rays diffract from a crystal in which a spacing between atomic planes is 0,175nm? The 2nd diffraction, m=2, occurs at 45o.

Homework Equations


Δr=2dcosθm=mλ
m+1/m = cos45/cosθm , because when the m increases the θm decreases.

The Attempt at a Solution


m+1/m = cos45/cosθ1
θ1 = 69o.

What do you think? Just asking because I am not 100% sure.
 
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Last time I checked, Bragg's law was m lambda = 2 d sin(theta)...

Higher order reflections always occur at larger Bragg angles.
 
I my case it is cosθm. Yep, I think this should be the right answer because the angle is bigger than 45o.
 

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