The coefficient of static friction on an unbanked curve

AI Thread Summary
A car traveling at 100 m/s on a 400 m radius unbanked turn with a static friction coefficient of 1.1 raises concerns about its ability to navigate the curve without crashing. The relevant equation indicates that the maximum speed for the car to maintain a circular path is determined by the frictional force. Calculating the maximum speed shows that the car exceeds this limit, implying it will not stay centered on the track. Consequently, the car is likely to crash into the outer wall. Understanding the dynamics of friction and speed is crucial for safe navigation on curves.
apt8
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Homework Statement


A car traveling at 100 m/s enters an unbanked turn of 400 m radius. The coefficient of static friction between the tires and track is 1.1. The track has both an inner and outer wall. Which statement is correct?


Homework Equations



v=<square root>coefficientmgr/m

The Attempt at a Solution



A. The car will crash into the outer wall.
B. The car will crash into the inner wall.
C. The car will stay in the center of the track.
D. The car will stay in the center of the track if the driver speeds up.
E. The car would stay in the center of the track if the radius were 200m.




please help!
 
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apt8 said:

Homework Statement


A car traveling at 100 m/s enters an unbanked turn of 400 m radius. The coefficient of static friction between the tires and track is 1.1. The track has both an inner and outer wall. Which statement is correct?


Homework Equations



v=<square root>coefficientmgr/m

The Attempt at a Solution



A. The car will crash into the outer wall.
B. The car will crash into the inner wall.
C. The car will stay in the center of the track.
D. The car will stay in the center of the track if the driver speeds up.
E. The car would stay in the center of the track if the radius were 200m.




please help!
you have the right equation; solve it for v and compare it to the given v. What does this imply? Please show some attempt.
 
thank you! that's all i needed
 
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