The collar B slides along a guide rod (Polar Coord.)

AI Thread Summary
The discussion revolves around the dynamics of a collar B sliding along a spiral guide rod defined by R = bθ. Participants are analyzing the acceleration components of the collar, specifically the radial (a_R) and angular (a_θ) accelerations. The radial acceleration is calculated as a_R = -\frac{π}{2} b ω^2, while the angular acceleration is given by a_θ = 2bω^2. There is a focus on ensuring the calculations are correct, particularly regarding the squared terms of the radial acceleration. The consensus is that the calculations presented appear accurate.
Alexanddros81
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Homework Statement


13.29 The colar B slides along a guide rod that has the shape of the spiral R = bθ.
A pin on the collar slides in the slotted arm OC. If OC is rotating at the constant angular
speed ##\dot θ = ω##, determine the magnitude of the acceleration of the collar when
it is a A.

P13_29-P13_30.jpg


Homework Equations

The Attempt at a Solution



Pytels_Dynamics067.jpg
[/B]

what aθ will be?
It is not 2. I have just left it unfinished.
 
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##\dot{R}## is not zero. Does ##R## not change as the collar slides?
 
##a_R = \ddot R - R\dot θ^2 = -\frac {π} {2} b ω^2## since ##R = bθ = bπ/2## and ##\dot R = b\dot θ = bω## and ##\ddot R = b\ddot θ = 0##

##a_θ = R\ddotθ + 2 \dot R \dotθ = 2bωω = 2bω^2##

Pytels_Dynamics068.jpg


Is this correct? is ##(-\frac {π} {2} b ω^2)^2 = \frac {π^2} {4} b^2 ω^4##
 
Last edited:
Alexanddros81 said:
##a_R = \ddot R - R\dot θ^2 = -\frac {π} {2} b ω^2## since ##R = bθ = bπ/2## and ##\dot R = b\dot θ = bω## and ##\ddot R = b\ddot θ = 0##

##a_θ = R\ddotθ + 2 \dot R \dotθ = 2bωω = 2bω^2##

View attachment 211420

Is this correct? is ##(-\frac {π} {2} b ω^2)^2 = \frac {π^2} {4} b^2 ω^4##
Looks right.
 
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