The Fundamental Theorem of Calculus

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SUMMARY

The discussion centers on evaluating the definite integral of the function (3/x² - 1) from 1 to 2, with the confirmed answer being 1/2. The participant initially miscalculated the antiderivative, mistakenly applying the power rule incorrectly. After correcting their approach, they derived the correct antiderivative and verified their result using the Fundamental Theorem of Calculus, confirming the answer through differentiation.

PREREQUISITES
  • Understanding of definite integrals and the Fundamental Theorem of Calculus
  • Familiarity with algebraic functions and their antiderivatives
  • Proficiency in using graphing utilities for verification
  • Knowledge of differentiation techniques
NEXT STEPS
  • Study the Fundamental Theorem of Calculus in detail
  • Practice evaluating definite integrals of various algebraic functions
  • Learn how to use graphing utilities for integral verification
  • Explore common mistakes in applying the power rule for differentiation
USEFUL FOR

Students studying calculus, educators teaching integral calculus, and anyone looking to improve their understanding of the Fundamental Theorem of Calculus and integral evaluation techniques.

thegoosegirl42
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Homework Statement


Evaluate the definite integral of the algebraic function. Use a graphing utility to verify your result.
Integral from [1 to 2] of (3/x^2 - 1)

Homework Equations


The answer is 1/2
f(x)dx= F(b) - F(a)

The Attempt at a Solution


I tried taking it to make it -x^-3 - 1x as the antiderivative but when I put 2 in and then 1 I don't get the answer.
 
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thegoosegirl42 said:
I tried taking it to make it -x^-3 - 1x as the antiderivative
Take the derivative to check your answer. Is it correct?
 
Nathanael said:
Take the derivative to check your answer. Is it correct?
Gosh dang it I was going down in exponent when I should have been going up. The new derivative would be -3x^-1 -1x making the answer be -3.5+4 Thus the answer is .5. Thank you so much.
 

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