Beginner@Phys
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Homework Statement
The figure shows a 230 g uniform rod pivoted at one end. The other end is attached to a horizontal spring. The spring is neither stretched nor compressed when the rod hangs straight down. K=3.0N/m and the length of the rod is 0.20m.
What is the rod's oscillation period? You can assume that the rod's angle from vertical is always small.
Homework Equations
Restorative force=F=-kΔx
Torque=Fd=force * length of lever arm
Moment of inertia for a rod pivoted about one end: I=(1/3)mL2
Angular frequency(w)=2π/T
The Attempt at a Solution
-kΔx=I*-w2Θ
<=>
-kr2Θ=I*-w2Θ
<=>
-kr2Θ/I=-w2Θ
Substitute I into the equation, L=r in this case.
-3K/M*Θ=-w2Θ
Therfore w=sqt(3K/M)
<=>
2π/T=sqt(3K/M)
<=>
T=2π/sqt(M/3K)=1.00s
But, I don't really know if my calculations are correct.