The Physics of Dropping a Magnet Through a Copper Tube

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When a cylindrical magnet is dropped through a copper tube, it experiences a slowing effect due to electromagnetic induction, creating eddy currents in the copper. These eddy currents generate an opposing magnetic field, resulting in a force that acts against the magnet's motion. If the tube is held while the magnet is dropped inside, the tube will indeed feel heavier due to the reaction force from the magnet's induced magnetic field. This interaction illustrates the principles of electromagnetic forces and Newton's third law of motion. The overall effect demonstrates the relationship between moving magnets and conductive materials.
robhlee
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Hello,

say you have a cylindrical magnet magnetized through thickness (not radially) and you drop it through a copper tube. It will slow down. Is there an opposite force on the tube? If you were to hold the tube in your hand and drop the magnet inside, would the tube feel heavier?
 
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Yes...
 
just wanted to make sure, thanks...........................................
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'

Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'

So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
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