Thermal Vac chamber pressure gain question

AI Thread Summary
A thermal vacuum chamber incident caused a pressure increase from 3.7E-7 to 5.0E-7 due to an abrupt gas release. To determine the volume of gas released, the ideal gas law (PV=nRT) can be applied, considering the chamber's dimensions and the pressures involved. Calculating the volume in liters and converting it to moles using standard conditions provides the amount of gas released. Contamination from pump oil or other sources may have contributed to the inability to maintain high vacuum levels. Understanding these dynamics is crucial for effective chamber operation and troubleshooting.
loctwo
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Hi group, I work at Thermal Vacuum Chamber, and we had an incident last night where our chamber, Which is 70' H x 30' D, was pumped down to a pressure of 3.7E-7. There was a release of gas into the chamber abruptly last night that caused the pressure in the chamber to rise to 5.0E-7, before it recovered back to it's original pressure. My question is How can I tell in liters how much gas was released into the chamber to cause this amount of rise in chamber pressure, based on the starting pressure and the ending pressure?
 
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Wow! both # are so far below viscus flow, it might be worth thinking about how many atoms we are talking about. (it's been over 30 years since I did vacuum stuff.)
From the interweb, http://en.wikipedia.org/wiki/Mean_free_path
In a chamber that size, I am thinking some type of contamination, even roughing pump oil out gases at 10 -7. I have seen a case where diffusion pump could not get to a high vacuum. It turned out that the diffusion pump oil was contaminated with another oil.
 
loctwo said:
Hi group, I work at Thermal Vacuum Chamber, and we had an incident last night where our chamber, Which is 70' H x 30' D, was pumped down to a pressure of 3.7E-7. There was a release of gas into the chamber abruptly last night that caused the pressure in the chamber to rise to 5.0E-7, before it recovered back to it's original pressure. My question is How can I tell in liters how much gas was released into the chamber to cause this amount of rise in chamber pressure, based on the starting pressure and the ending pressure?

Use the ideal gas law (PV=nRT) with a pressure of 1.3E-7.
 
Calculate the volume of the chamber in liters.
Divide by the standard molar volume of a gas at STP (22.41 liters)
Multiply this volume by 3.0E-7/760 and 5.0E-7/760 to get moles of gas before and after.
Subtract and get gas released into chamber, in moles (e.g., 29 grams per mole of air).
 
Did the incident occur while the evacuation was going on?
 
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